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第2045题:linear equations



If the system of linear equations 


{x+ky+3z=03x+ky2z=02x+4y3z=0\begin{cases} x+ky+3z=0 \\ 3x+ky-2z=0 \\ 2x+4y-3z=0 \end{cases}


has a non-zero slution (x,y,z) (x,y,z) , then xzy2\dfrac{xz}{y^2} is (   ).

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