第2190题:二次型的分类
以下哪个二次型正定?
A.f(x1,x2,x3)=−2x12−6x22−4x32 +2x1x2+2x1x3
B. f(x1,x2,x3)=x12+2x22−3x32 +4x1x2+2x2x3
C. f(x1,x2,x3)= x12+x22+x32−2x1x3
D. f(x1,x2,x3)= 2x12+5x22+5x32 +4x1x2−4x1x3−8x2x3