第2187题:二次曲面
上图为双叶双曲面的图形,以下哪方程是的图形是双叶双曲面?
A. x2a2+y2b2+z2c2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}=1a2x2+b2y2+c2z2=1
B. x2a2+y2b2−z2c2=1\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}-\dfrac{z^2}{c^2}=1a2x2+b2y2−c2z2=1
C. x2a2−y2b2−z2c2=1 \dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}-\dfrac{z^2}{c^2}=1a2x2−b2y2−c2z2=1
D. x2a2−y2b2=1\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1a2x2−b2y2=1